2y^2+4y+2=2y(y+2)

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Solution for 2y^2+4y+2=2y(y+2) equation: 


Simplifying
2y2 + 4y + 2 = 2y(y + 2)

Reorder the terms:
2 + 4y + 2y2 = 2y(y + 2)

Reorder the terms:
2 + 4y + 2y2 = 2y(2 + y)
2 + 4y + 2y2 = (2 * 2y + y * 2y)
2 + 4y + 2y2 = (4y + 2y2)

Add '-4y' to each side of the equation.
2 + 4y + -4y + 2y2 = 4y + -4y + 2y2

Combine like terms: 4y + -4y = 0
2 + 0 + 2y2 = 4y + -4y + 2y2
2 + 2y2 = 4y + -4y + 2y2

Combine like terms: 4y + -4y = 0
2 + 2y2 = 0 + 2y2
2 + 2y2 = 2y2

Add '-2y2' to each side of the equation.
2 + 2y2 + -2y2 = 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
2 + 0 = 2y2 + -2y2
2 = 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
2 = 0

Solving
2 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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